nun 21

nun #21 This one was originally posted and created on http://www.otherbiblecode.com/ by Vernon Jenkins. The website is no longer there. His new website is www.whatabeginning.com .Read on for my contribution.

In the Hebrew alphabet the letters can also correspond to 1-9,10-90, and 100-400 and the last 5 letters are the same as their original forms.

So in Genesis 1:1 there are 7 words with the following numbers:

913, 203,86,401,395,407, and 296.

Now 913+203+86+401+395+407+296=2701.

913*203*86*401*395*407*296=304,153,525,784,175,760

If we add the numbers between commas, 304+153+525+784+175+760=2701! See #21, #88, #45, #46, #49, #55, #89, #63, #69, #70, #72, #74, #76, #80, #82, #84 and #85.

Vernon Jenkins also pointed out a verse in Genesis where the earth started over after Noah and the letters also added to 2701.

Not only that, 2701=37*73.

And not only that, 37 and 73 are among the first centered Star of David numbers. 37 is the 4th centered hexagonal number and 37 and 73 are the second and third Star of David numbers. We will see a pattern with that next. Obviously, this pattern only works starting with beit.

It should also be noted that Vernon Jenkins found a verse in Noah describing a new beginning where the letters added up to 2701 also.

The next part is all mine.

But first, I have found something remarkable today February 17, 2022 about furthering this pattern. This is me:

Note that 73 is the gematria for Chokmah or wisdom.

Many Jews consider the first Beit to be 2000 instead of 2 because it is large. If we add up all the words/letters with 2000 instead of 2 the number is 1998 higher and we get 4699. 4,699 is factored by 37 and 127. 37 is the 4th centered hexagonal number as we know and 127 turns out to be the 9th.

And there’s more. If we multiply the numbers (from words) with 2911 instead of 913 we get 969,760,036,755,460,720 just like before. The numbers between commas add up to 3700!

And there’s more that I found. Joseph Smith said there was no beit so that would give the first word as 911. The word sum, 2699, cannot be divisible by 37 for obvious reasons, but I found it was prime. When we multiply all the words we get 303,487,253,000,420,720. When we add the numbers between commas we get 2183 = 37 times 59. Not bad for Joseph Smith. 37 we’ve seen again and note that 37 occurring is not trivial. 59 is 2 below 61, another centered hexagon number and we have subtracted 2 in the verse as well as a hexagon number.

Next, I remember hearing that the first B can be 2 million so I tried it. 2,000,911*203*86*401*395*407*296= 666,576,271,008,040,420,720. 666+576+271+8+40+420+720 = 2701 again! 37*73.

I tried 2 billion. 2,000,000,911*203*86*401*395*407*296 = 666,273,087,242,293,000,420,720.

666+273+87+242+293+0+420+720 = 2701 again! This can’t keep up!

I tried 2 trillion. 2,000,000,000,911*203*86*401*395*407*296 = 666,272,784,058,527,253,000,420,720. 666+272+784+58+527+253+0+420+720 = 3700 again.

2 quadrillion. 2,000,000,000,000,911*203*86*401*395*407*296 =

666,272,783,755,343,487,253,000,420,720.

666+272+783+755+343+487+253+0+420+720 = 4699 which is 37*127 again.

2 quintillion 2,000,000,000,000,000,911*203*86*401*395*407*296 =

666,272,783,755,040,303,487,253,000,420,720.

666+272+783+755+40+303+487+253+0+420+720 = 4699 again.

At sextillion “000”s just fill in between the 40 and 303. There’s just one more pair of 000s each time, so it is 4699 forever.

B=                   words added                                                   multiply and add between commas

0 (no B)           2699                                                                2183=37*59

2 (normal)        2701=37*73                                                    2701=37*73

2000                4699=37*127                                                  3700=2*2*5*5*37

2 million          2mil2699=37*54127=37*113*479                 2701=37*73

2 billion           2bil2699=37*54054127=37*263*205529      2701=37*73

2 trillion           2tril2699=37*54054054127                           3700=2*2*5*5*37

Every multiple of 1000 afterwards     follows pattern            4699=37*127

(notice that each 54… rounds to 541, Israel (I+Sh+R+A+L=10+300+200+1+30). See #1, #10, #21, #45, #40, #74, #76 and #79. Plus 5405… is like 540*5+1=2701.

Beit final Tzaddik #41 even relating the numbers multiplied by 37. Mine.

We get 59, 73, 100, 113, and 127. Their differences are 14,27, 13 and 14, and 27 between 100 and 127. 13 and 14 are the average of 0 and 27.

For 263, we subtract 263 from 127 as we should. 136 is 13+13+37+73, where 13 is the minimal Star of David number. I’m sorry 13 had to be twice but it works. 479=9*37+2*73. For 205529, 205+529 = 734. 734 = 8*37+6*73.